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~ Winners List for Puzzle # 106 ~
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David Belanger
St. Michael's School - Belleville, ON
Stephen Britten
St.F.X. - Bachelor of Education
lmeadows@brill.acomp.usf.edu
Will Judson - Ms. Beth Cross's Class
St. Anne School - Sarnia, Ont.
Angela Bossio
Stuart Wood School - Kamloops B.C
Mr. John VanLieshout's Grade 6/7 class
St.Peter Canisius School - Watford, Ontario
Matt Cosulich - Mrs .Harris class grade 7\8
brookville Public school
Matthew Dalton - Gr. 10
MVHS - Miramichi NB
Grade 8Y Class
Grenville Christian College of Brockville, On.
Jean-Francois Latour
Whitehorse, Yukon, CANADA
John Mackie
Bear Lake School - Bear Lake, B.C.
Annie Shaw - Grade 6 Mr. Czenda
C.H. Bray - Ancaster
Natalie Delorey
Bachelor of Education Program Saint Francis Xavier University
E-Mail: x92jva@juliet.stfx.ca Homepage:http//juliet.stfx.ca/~x92jva
Mrs. Johnston's Class
Sheridan Public School
Andrea Wilkinson and Diana Phillips
Shamrock School - Winnipeg, MB
Class 4/5M
St. John the Baptist-King Edward School - Saint John, New Brunswick
Eamonn Murtagh
St. Thomas' Senior - NS,
Jobstown, Tallaght, Dublin, 24.
the brother team of:
(a) Tim Wootton, grade 8,
Pontiac Protestant High School - Shawville, Quebec
(b) Jess Wootton Grade 6
Dr. S.E. McDowell school - Shawville Que.
Melissa and Sheila - T. Burnie's Grade 7/8 class
St Ann School - Toronto, Ontario
Bryan Ibeas, John Paul Rimando, Rui Fernandes and Michael DeCiantis - O.
Piruckyj's Grade 8 class
D'Arcy McGee School - Toronto, Ontario
Christopher Ridge, Andrew Walker
grade 3 Joseph Welsh School
Red Deer, Alberta
Stefanie a. Gr. 5
Grant A.- Gr. 4
Beaverlodge Elementary School - Winnipeg,Mb.,Canada
http://www.mbnet.mb.ca/~marmarti
Sean Reynolds Grade 6
St. Marguerit d'Youville Catholic School - Whitby, Ontario, Canada
Roxana Bartolome - Grade 5
Cottage Lane School- Blauvelt, New York
Sugreev Chawla
Beers Street Middle School - Hazlet, New Jersey
Julie Langan 5/6th grade - Mr. J. Cowley
Our Lady of Mercy Elementary School - Sarnia, Ontario
------- other rationale ------
& +++++++343++++++++ &
answer 343
Kyle
Beaverlodge Elementary School
http://www.mbnet.mb.ca/~marmarti
Kyle solved it this way: the differences between the numbers
are 7,19, 37, 61 and 91. They go up in a pattern of +12 ( 7+12=19),
+18 (19+18=37), +24(24+37=61) +30(30+61=91), +36(91+36=127)
so 216+127=343
& +++++++343++++++++ &
answer 343
Melanie Kushman, Gr 9
Blaire Hamilton, Gr 9
Western Christian College - Dauphin, Manitoba
Here's how I did it...I took the original list of numbers and
found the differences between each of them, then, I found the
differences between the set of numbers in the differences list.
Then I did the process one more time, and found that the difference
was always 6. So I was added 6 to the last number in the second row,
and got 36. Then I added 36 to the last number in the third row and
got 127. And finally I added 127 to the last number in the bottom
row and got the answer, 343.
6 6 6 6
12 18 24 30 36
7 19 37 61 91 127
1 8 27 64 125 216 343
& +++++++343++++++++ &
answer 343
Jenn Barclay - Grade 6 Mr. Czerneda
C.H. Bray - Ancaster
The difference between 1 and 8 is 7. The difference between
8 and 27 is 19. The difference between 27 and 64 is 37.
The difference between 64 and 125 is 61. The difference between
125 and 216 is 91. Now, the difference between 7 and 19 is 12.
The difference between 19 and 37 is 18. The difference between
37 and 61 is 24. The difference between 61 and 91 is 30. So
first you have the original number, then you have the difference
between the numbers, then you have the difference between the
difference. That is where the pattern is. You always add six.
So I added six and got 36. Then I add 36 to the last difference
91 and got 127. 127 plus 216 is 343.
& +++++++361++++++++ &
answer 361
Nate Charach and Alex Duffy
Kane Middle School, City of York, Ontario
Explanation: by casting out nines determined pattern of 1,8,9,
as sum of digits. sum of diferences between adjacent numbers
resulted in pattern of 7,10,10,7,10, thus they concluded next
number must be 1 and sum of digits must be 1. 361 gives sum of 1
and difference is 145 which gives sum of 1. Matches the pattern.
& +++++++347++++++++ &
answer 347
Vance De Waele - Mr. Butler's grade 6
Rothesay Park Elementary School - New Brunswick class.
DENNIS E BUTLER,butledee@nbed.nb.ca
We calculated the difference between each number. And then, we
calculated the difference between the new numbers we had. We
reapeated that step one last time and it gave us the following
digits: 10 6 6 and then it seemed logical that the next number
to follow these numbers would be 10. So we were left with 10 6 6 10.
We calculated the difference with these numbers until we had 0.
Then we reversed the process until we finally got the answer 347.
///////comment///////
the step from 10, 6, 6, to 10 seems a bit of a leap////////
& +++++++313++++++++ &
answer 313
Stephen Manual, Matthew Sheppard, MAtthew Mckay, and Paul Ryan.
Enrichment Program
St. Stephen's Elementary - Stephenville, Newfoundland.
We tink the answer is 313, since when you see how much the number
increases each time the pattern was 7,19,37,61,91. WE found that the
pATTERNWAS INCREASED BY 6 EACh time, so 91 +6 is 97, so add the 97 to
216, you get 313.
///////comment///////
the last difference was not 6 it was (91-61)=30 so maybe
you should add 36 (91+36)=127....then 216+127 = 343////////
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