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~ Winners/Solvers of puzzle #413 ~
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Mrs. Spence's 3/4 Class
Joseph Welsh School - Red Deer AB Canada
Alombert, Bill
Bordeaux University - France
Grade 5 - Spence's Super Students
Normandeau School - Red Deer AB CANADA
Alternate answer 2355 from Yury - WOW ... follow this one through!
Normandeau School - Red Deer AB CANADA
Add the digits in each number. The sums are 9, 10, 10, 12, 11, 11, ?
This shows two interlaced patterns: 9, 12, (15) --increasing by three each time
and 10, 10, 11, 11,...--pairs, increasing by 1 each time.
So the sum of the digits on the next number should be 15.
Alternating terms also show repetition of the starting digits 22 and 23,
so the missing term should start 23.
Except for 57, all the numbers end in 5. There are three before 57, so
there should be three after 57 that end in 5.
So the number starts 23 and ends 5 and sums to 15. The missing digit must
also be 5: 2355
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Compiled by Anne Morrow.
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